Using the paired t-test

The hypothesis, the differences between pairs, is zero.^[1]

Requiremenets:
The measured differences are normally distributed.

For now, I don’t know if the differences are normally distributed. I have to assume it’s true.

The t value is calculated by this formula

$$
t=\frac{m_1-m_2}{SE}
$$

SE is the standard error. \(SE = \frac{\sigma}{\sqrt{n}}\). \(\sigma\) is the standard deviation, and n is the (population) size.

References

1. . The Paired 𝑡 -test. . [2026-03-18].[↩]